Metamath Proof Explorer


Theorem eqtr3id

Description: An equality transitivity deduction. (Contributed by NM, 5-Aug-1993)

Ref Expression
Hypotheses eqtr3id.1 𝐵 = 𝐴
eqtr3id.2 ( 𝜑𝐵 = 𝐶 )
Assertion eqtr3id ( 𝜑𝐴 = 𝐶 )

Proof

Step Hyp Ref Expression
1 eqtr3id.1 𝐵 = 𝐴
2 eqtr3id.2 ( 𝜑𝐵 = 𝐶 )
3 1 eqcomi 𝐴 = 𝐵
4 3 2 syl5eq ( 𝜑𝐴 = 𝐶 )