Metamath Proof Explorer


Theorem eqtr3id

Description: An equality transitivity deduction. (Contributed by NM, 5-Aug-1993)

Ref Expression
Hypotheses eqtr3id.1 ⊢ 𝐵 = 𝐴
eqtr3id.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
Assertion eqtr3id ( 𝜑 → 𝐴 = 𝐶 )

Proof

Step Hyp Ref Expression
1 eqtr3id.1 ⊢ 𝐵 = 𝐴
2 eqtr3id.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
3 1 eqcomi ⊢ 𝐴 = 𝐵
4 3 2 eqtrid ⊢ ( 𝜑 → 𝐴 = 𝐶 )