Metamath Proof Explorer


Theorem exp58

Description: An exportation inference. (Contributed by Jeff Hankins, 7-Jul-2009)

Ref Expression
Hypothesis exp58.1 ( ( ( 𝜑𝜓 ) ∧ ( ( 𝜒𝜃 ) ∧ 𝜏 ) ) → 𝜂 )
Assertion exp58 ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏𝜂 ) ) ) ) )

Proof

Step Hyp Ref Expression
1 exp58.1 ( ( ( 𝜑𝜓 ) ∧ ( ( 𝜒𝜃 ) ∧ 𝜏 ) ) → 𝜂 )
2 1 ex ( ( 𝜑𝜓 ) → ( ( ( 𝜒𝜃 ) ∧ 𝜏 ) → 𝜂 ) )
3 2 exp5g ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏𝜂 ) ) ) ) )