Theorem exp5g

Description: An exportation inference. (Contributed by Jeff Hankins, 7-Jul-2009)

	Ref	Expression
Hypothesis	exp5g.1	⊢ ( ( 𝜑 ∧ 𝜓 ) → ( ( ( 𝜒 ∧ 𝜃 ) ∧ 𝜏 ) → 𝜂 ) )
Assertion	exp5g	⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) ) )

Proof

Step	Hyp	Ref	Expression
1		exp5g.1	⊢ ( ( 𝜑 ∧ 𝜓 ) → ( ( ( 𝜒 ∧ 𝜃 ) ∧ 𝜏 ) → 𝜂 ) )
2	1	exp4c	⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) )
3	2	ex	⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) ) )