Metamath Proof Explorer


Theorem exp5c

Description: An exportation inference. (Contributed by Jeff Hankins, 7-Jul-2009)

Ref Expression
Hypothesis exp5c.1 ⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → ( ( 𝜃 ∧ 𝜏 ) → 𝜂 ) ) )
Assertion exp5c ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) ) )

Proof

Step Hyp Ref Expression
1 exp5c.1 ⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → ( ( 𝜃 ∧ 𝜏 ) → 𝜂 ) ) )
2 1 exp4a ⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) )
3 2 expd ⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) ) )