Metamath Proof Explorer


Theorem expimpd

Description: Exportation followed by a deduction version of importation. (Contributed by NM, 6-Sep-2008)

Ref Expression
Hypothesis expimpd.1 ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜒 → 𝜃 ) )
Assertion expimpd ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) )

Proof

Step Hyp Ref Expression
1 expimpd.1 ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜒 → 𝜃 ) )
2 1 ex ⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → 𝜃 ) ) )
3 2 impd ⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) )