Metamath Proof Explorer
Description: A function with empty domain is empty. (Contributed by Alexander van der
Vekens, 30-Jun-2018)
|
|
Ref |
Expression |
|
Assertion |
f0bi |
⊢ ( 𝐹 : ∅ ⟶ 𝑋 ↔ 𝐹 = ∅ ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
ffn |
⊢ ( 𝐹 : ∅ ⟶ 𝑋 → 𝐹 Fn ∅ ) |
| 2 |
|
fn0 |
⊢ ( 𝐹 Fn ∅ ↔ 𝐹 = ∅ ) |
| 3 |
1 2
|
sylib |
⊢ ( 𝐹 : ∅ ⟶ 𝑋 → 𝐹 = ∅ ) |
| 4 |
|
f0 |
⊢ ∅ : ∅ ⟶ 𝑋 |
| 5 |
|
feq1 |
⊢ ( 𝐹 = ∅ → ( 𝐹 : ∅ ⟶ 𝑋 ↔ ∅ : ∅ ⟶ 𝑋 ) ) |
| 6 |
4 5
|
mpbiri |
⊢ ( 𝐹 = ∅ → 𝐹 : ∅ ⟶ 𝑋 ) |
| 7 |
3 6
|
impbii |
⊢ ( 𝐹 : ∅ ⟶ 𝑋 ↔ 𝐹 = ∅ ) |