Metamath Proof Explorer


Theorem f1imaen3g

Description: If a set function is one-to-one, then a subset of its domain is equinumerous to the image of that subset. (This version of f1imaeng does not need ax-rep nor ax-pow .) (Contributed by BTernaryTau, 13-Jan-2025)

Ref Expression
Assertion f1imaen3g ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐶 ⊆ 𝐴 ∧ 𝐹 ∈ 𝑉 ) → 𝐶 ≈ ( 𝐹 “ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 resexg ⊢ ( 𝐹 ∈ 𝑉 → ( 𝐹 ↾ 𝐶 ) ∈ V )
2 1 3ad2ant3 ⊢ ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐶 ⊆ 𝐴 ∧ 𝐹 ∈ 𝑉 ) → ( 𝐹 ↾ 𝐶 ) ∈ V )
3 f1ores ⊢ ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐶 ⊆ 𝐴 ) → ( 𝐹 ↾ 𝐶 ) : 𝐶 –1-1-onto→ ( 𝐹 “ 𝐶 ) )
4 3 3adant3 ⊢ ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐶 ⊆ 𝐴 ∧ 𝐹 ∈ 𝑉 ) → ( 𝐹 ↾ 𝐶 ) : 𝐶 –1-1-onto→ ( 𝐹 “ 𝐶 ) )
5 f1oen3g ⊢ ( ( ( 𝐹 ↾ 𝐶 ) ∈ V ∧ ( 𝐹 ↾ 𝐶 ) : 𝐶 –1-1-onto→ ( 𝐹 “ 𝐶 ) ) → 𝐶 ≈ ( 𝐹 “ 𝐶 ) )
6 2 4 5 syl2anc ⊢ ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐶 ⊆ 𝐴 ∧ 𝐹 ∈ 𝑉 ) → 𝐶 ≈ ( 𝐹 “ 𝐶 ) )