Metamath Proof Explorer


Theorem f1oeq2

Description: Equality theorem for one-to-one onto functions. (Contributed by NM, 10-Feb-1997)

Ref Expression
Assertion f1oeq2 ( 𝐴 = 𝐵 → ( 𝐹 : 𝐴 –1-1-onto→ 𝐶 ↔ 𝐹 : 𝐵 –1-1-onto→ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 f1eq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐹 : 𝐴 –1-1→ 𝐶 ↔ 𝐹 : 𝐵 –1-1→ 𝐶 ) )
2 foeq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐹 : 𝐴 –onto→ 𝐶 ↔ 𝐹 : 𝐵 –onto→ 𝐶 ) )
3 1 2 anbi12d ⊢ ( 𝐴 = 𝐵 → ( ( 𝐹 : 𝐴 –1-1→ 𝐶 ∧ 𝐹 : 𝐴 –onto→ 𝐶 ) ↔ ( 𝐹 : 𝐵 –1-1→ 𝐶 ∧ 𝐹 : 𝐵 –onto→ 𝐶 ) ) )
4 df-f1o ⊢ ( 𝐹 : 𝐴 –1-1-onto→ 𝐶 ↔ ( 𝐹 : 𝐴 –1-1→ 𝐶 ∧ 𝐹 : 𝐴 –onto→ 𝐶 ) )
5 df-f1o ⊢ ( 𝐹 : 𝐵 –1-1-onto→ 𝐶 ↔ ( 𝐹 : 𝐵 –1-1→ 𝐶 ∧ 𝐹 : 𝐵 –onto→ 𝐶 ) )
6 3 4 5 3bitr4g ⊢ ( 𝐴 = 𝐵 → ( 𝐹 : 𝐴 –1-1-onto→ 𝐶 ↔ 𝐹 : 𝐵 –1-1-onto→ 𝐶 ) )