Metamath Proof Explorer


Theorem feq123

Description: Equality theorem for functions. (Contributed by FL, 16-Nov-2008)

Ref Expression
Assertion feq123 ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐶 ∧ 𝐵 = 𝐷 ) → ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ 𝐺 : 𝐶 ⟶ 𝐷 ) )

Proof

Step Hyp Ref Expression
1 simp1 ⊢ ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐶 ∧ 𝐵 = 𝐷 ) → 𝐹 = 𝐺 )
2 simp2 ⊢ ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐶 ∧ 𝐵 = 𝐷 ) → 𝐴 = 𝐶 )
3 simp3 ⊢ ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐶 ∧ 𝐵 = 𝐷 ) → 𝐵 = 𝐷 )
4 1 2 3 feq123d ⊢ ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐶 ∧ 𝐵 = 𝐷 ) → ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ 𝐺 : 𝐶 ⟶ 𝐷 ) )