Metamath Proof Explorer


Theorem feq123

Description: Equality theorem for functions. (Contributed by FL, 16-Nov-2008)

Ref Expression
Assertion feq123 ⊢ F = G ∧ A = C ∧ B = D → F : A ⟶ B ↔ G : C ⟶ D

Proof

Step Hyp Ref Expression
1 simp1 ⊢ F = G ∧ A = C ∧ B = D → F = G
2 simp2 ⊢ F = G ∧ A = C ∧ B = D → A = C
3 simp3 ⊢ F = G ∧ A = C ∧ B = D → B = D
4 1 2 3 feq123d ⊢ F = G ∧ A = C ∧ B = D → F : A ⟶ B ↔ G : C ⟶ D