Metamath Proof Explorer


Theorem frege58bcor

Description: Lemma for frege59b . (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege58bcor ( ∀ 𝑥 ( 𝜑𝜓 ) → ( [ 𝑦 / 𝑥 ] 𝜑 → [ 𝑦 / 𝑥 ] 𝜓 ) )

Proof

Step Hyp Ref Expression
1 ax-frege58b ( ∀ 𝑥 ( 𝜑𝜓 ) → [ 𝑦 / 𝑥 ] ( 𝜑𝜓 ) )
2 sbim ( [ 𝑦 / 𝑥 ] ( 𝜑𝜓 ) ↔ ( [ 𝑦 / 𝑥 ] 𝜑 → [ 𝑦 / 𝑥 ] 𝜓 ) )
3 1 2 sylib ( ∀ 𝑥 ( 𝜑𝜓 ) → ( [ 𝑦 / 𝑥 ] 𝜑 → [ 𝑦 / 𝑥 ] 𝜓 ) )