Metamath Proof Explorer


Theorem frege68c

Description: Combination of applying a definition and applying it to a specific instance. Proposition 68 of Frege1879 p. 54. (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis frege59c.a 𝐴𝐵
Assertion frege68c ( ( ∀ 𝑥 𝜑𝜓 ) → ( 𝜓[ 𝐴 / 𝑥 ] 𝜑 ) )

Proof

Step Hyp Ref Expression
1 frege59c.a 𝐴𝐵
2 frege57aid ( ( ∀ 𝑥 𝜑𝜓 ) → ( 𝜓 → ∀ 𝑥 𝜑 ) )
3 1 frege67c ( ( ( ∀ 𝑥 𝜑𝜓 ) → ( 𝜓 → ∀ 𝑥 𝜑 ) ) → ( ( ∀ 𝑥 𝜑𝜓 ) → ( 𝜓[ 𝐴 / 𝑥 ] 𝜑 ) ) )
4 2 3 ax-mp ( ( ∀ 𝑥 𝜑𝜓 ) → ( 𝜓[ 𝐴 / 𝑥 ] 𝜑 ) )