Metamath Proof Explorer


Theorem frnnn0suppg

Description: Version of frnnn0supp avoiding ax-rep by assuming F is a set rather than its domain I . (Contributed by SN, 5-Aug-2024)

Ref Expression
Assertion frnnn0suppg ( ( 𝐹𝑉𝐹 : 𝐼 ⟶ ℕ0 ) → ( 𝐹 supp 0 ) = ( 𝐹 “ ℕ ) )

Proof

Step Hyp Ref Expression
1 c0ex 0 ∈ V
2 frnsuppeqg ( ( 𝐹𝑉 ∧ 0 ∈ V ) → ( 𝐹 : 𝐼 ⟶ ℕ0 → ( 𝐹 supp 0 ) = ( 𝐹 “ ( ℕ0 ∖ { 0 } ) ) ) )
3 1 2 mpan2 ( 𝐹𝑉 → ( 𝐹 : 𝐼 ⟶ ℕ0 → ( 𝐹 supp 0 ) = ( 𝐹 “ ( ℕ0 ∖ { 0 } ) ) ) )
4 3 imp ( ( 𝐹𝑉𝐹 : 𝐼 ⟶ ℕ0 ) → ( 𝐹 supp 0 ) = ( 𝐹 “ ( ℕ0 ∖ { 0 } ) ) )
5 dfn2 ℕ = ( ℕ0 ∖ { 0 } )
6 5 imaeq2i ( 𝐹 “ ℕ ) = ( 𝐹 “ ( ℕ0 ∖ { 0 } ) )
7 4 6 eqtr4di ( ( 𝐹𝑉𝐹 : 𝐼 ⟶ ℕ0 ) → ( 𝐹 supp 0 ) = ( 𝐹 “ ℕ ) )