Metamath Proof Explorer


Theorem fsovcnvfvd

Description: The value of the converse of ( A O B ) , where O is the operator which maps between maps from one base set to subsets of the second to maps from the second base set to subsets of the first for base sets, evaluated at function F . (Contributed by RP, 27-Apr-2021)

Ref Expression
Hypotheses fsovd.fs 𝑂 = ( 𝑎 ∈ V , 𝑏 ∈ V ↦ ( 𝑓 ∈ ( 𝒫 𝑏m 𝑎 ) ↦ ( 𝑦𝑏 ↦ { 𝑥𝑎𝑦 ∈ ( 𝑓𝑥 ) } ) ) )
fsovd.a ( 𝜑𝐴𝑉 )
fsovd.b ( 𝜑𝐵𝑊 )
fsovfvd.g 𝐺 = ( 𝐴 𝑂 𝐵 )
fsovcnvfvd.f ( 𝜑𝐹 ∈ ( 𝒫 𝐴m 𝐵 ) )
Assertion fsovcnvfvd ( 𝜑 → ( 𝐺𝐹 ) = ( 𝑦𝐴 ↦ { 𝑥𝐵𝑦 ∈ ( 𝐹𝑥 ) } ) )

Proof

Step Hyp Ref Expression
1 fsovd.fs 𝑂 = ( 𝑎 ∈ V , 𝑏 ∈ V ↦ ( 𝑓 ∈ ( 𝒫 𝑏m 𝑎 ) ↦ ( 𝑦𝑏 ↦ { 𝑥𝑎𝑦 ∈ ( 𝑓𝑥 ) } ) ) )
2 fsovd.a ( 𝜑𝐴𝑉 )
3 fsovd.b ( 𝜑𝐵𝑊 )
4 fsovfvd.g 𝐺 = ( 𝐴 𝑂 𝐵 )
5 fsovcnvfvd.f ( 𝜑𝐹 ∈ ( 𝒫 𝐴m 𝐵 ) )
6 eqid ( 𝐵 𝑂 𝐴 ) = ( 𝐵 𝑂 𝐴 )
7 1 2 3 4 6 fsovcnvd ( 𝜑 𝐺 = ( 𝐵 𝑂 𝐴 ) )
8 7 fveq1d ( 𝜑 → ( 𝐺𝐹 ) = ( ( 𝐵 𝑂 𝐴 ) ‘ 𝐹 ) )
9 1 3 2 6 5 fsovfvd ( 𝜑 → ( ( 𝐵 𝑂 𝐴 ) ‘ 𝐹 ) = ( 𝑦𝐴 ↦ { 𝑥𝐵𝑦 ∈ ( 𝐹𝑥 ) } ) )
10 8 9 eqtrd ( 𝜑 → ( 𝐺𝐹 ) = ( 𝑦𝐴 ↦ { 𝑥𝐵𝑦 ∈ ( 𝐹𝑥 ) } ) )