Metamath Proof Explorer


Theorem fss

Description: Expanding the codomain of a mapping. (Contributed by NM, 10-May-1998) (Proof shortened by Andrew Salmon, 17-Sep-2011)

Ref Expression
Assertion fss ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → 𝐹 : 𝐴 ⟶ 𝐶 )

Proof

Step Hyp Ref Expression
1 sstr2 ⊢ ( ran 𝐹 ⊆ 𝐵 → ( 𝐵 ⊆ 𝐶 → ran 𝐹 ⊆ 𝐶 ) )
2 1 com12 ⊢ ( 𝐵 ⊆ 𝐶 → ( ran 𝐹 ⊆ 𝐵 → ran 𝐹 ⊆ 𝐶 ) )
3 2 anim2d ⊢ ( 𝐵 ⊆ 𝐶 → ( ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐵 ) → ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐶 ) ) )
4 df-f ⊢ ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐵 ) )
5 df-f ⊢ ( 𝐹 : 𝐴 ⟶ 𝐶 ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐶 ) )
6 3 4 5 3imtr4g ⊢ ( 𝐵 ⊆ 𝐶 → ( 𝐹 : 𝐴 ⟶ 𝐵 → 𝐹 : 𝐴 ⟶ 𝐶 ) )
7 6 impcom ⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → 𝐹 : 𝐴 ⟶ 𝐶 )