Metamath Proof Explorer


Theorem funbrafv

Description: The second argument of a binary relation on a function is the function's value, analogous to funbrfv . (Contributed by Alexander van der Vekens, 25-May-2017)

Ref Expression
Assertion funbrafv ( Fun 𝐹 → ( 𝐴 𝐹 𝐵 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 funrel ⊢ ( Fun 𝐹 → Rel 𝐹 )
2 releldm ⊢ ( ( Rel 𝐹 ∧ 𝐴 𝐹 𝐵 ) → 𝐴 ∈ dom 𝐹 )
3 funbrafvb ⊢ ( ( Fun 𝐹 ∧ 𝐴 ∈ dom 𝐹 ) → ( ( 𝐹 ''' 𝐴 ) = 𝐵 ↔ 𝐴 𝐹 𝐵 ) )
4 3 biimprd ⊢ ( ( Fun 𝐹 ∧ 𝐴 ∈ dom 𝐹 ) → ( 𝐴 𝐹 𝐵 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) )
5 4 expcom ⊢ ( 𝐴 ∈ dom 𝐹 → ( Fun 𝐹 → ( 𝐴 𝐹 𝐵 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) ) )
6 2 5 syl ⊢ ( ( Rel 𝐹 ∧ 𝐴 𝐹 𝐵 ) → ( Fun 𝐹 → ( 𝐴 𝐹 𝐵 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) ) )
7 6 ex ⊢ ( Rel 𝐹 → ( 𝐴 𝐹 𝐵 → ( Fun 𝐹 → ( 𝐴 𝐹 𝐵 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) ) ) )
8 7 com14 ⊢ ( 𝐴 𝐹 𝐵 → ( 𝐴 𝐹 𝐵 → ( Fun 𝐹 → ( Rel 𝐹 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) ) ) )
9 8 pm2.43i ⊢ ( 𝐴 𝐹 𝐵 → ( Fun 𝐹 → ( Rel 𝐹 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) ) )
10 9 com13 ⊢ ( Rel 𝐹 → ( Fun 𝐹 → ( 𝐴 𝐹 𝐵 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) ) )
11 1 10 syl ⊢ ( Fun 𝐹 → ( Fun 𝐹 → ( 𝐴 𝐹 𝐵 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) ) )
12 11 pm2.43i ⊢ ( Fun 𝐹 → ( 𝐴 𝐹 𝐵 → ( 𝐹 ''' 𝐴 ) = 𝐵 ) )