Metamath Proof Explorer


Theorem funbrfvb

Description: Equivalence of function value and binary relation. (Contributed by NM, 26-Mar-2006)

Ref Expression
Assertion funbrfvb ( ( Fun 𝐹𝐴 ∈ dom 𝐹 ) → ( ( 𝐹𝐴 ) = 𝐵𝐴 𝐹 𝐵 ) )

Proof

Step Hyp Ref Expression
1 funfn ( Fun 𝐹𝐹 Fn dom 𝐹 )
2 fnbrfvb ( ( 𝐹 Fn dom 𝐹𝐴 ∈ dom 𝐹 ) → ( ( 𝐹𝐴 ) = 𝐵𝐴 𝐹 𝐵 ) )
3 1 2 sylanb ( ( Fun 𝐹𝐴 ∈ dom 𝐹 ) → ( ( 𝐹𝐴 ) = 𝐵𝐴 𝐹 𝐵 ) )