Metamath Proof Explorer
		
		
		
		Description:  Equivalence of function value and binary relation.  (Contributed by NM, 26-Mar-2006)
		
			
				
					 | 
					 | 
					Ref | 
					Expression | 
				
				
					 | 
					Assertion | 
					funbrfvb | 
					⊢  ( ( Fun  𝐹  ∧  𝐴  ∈  dom  𝐹 )  →  ( ( 𝐹 ‘ 𝐴 )  =  𝐵  ↔  𝐴 𝐹 𝐵 ) )  | 
				
			
		
		
			
				Proof
				
					
						| Step | 
						Hyp | 
						Ref | 
						Expression | 
					
						
							| 1 | 
							
								
							 | 
							funfn | 
							⊢ ( Fun  𝐹  ↔  𝐹  Fn  dom  𝐹 )  | 
						
						
							| 2 | 
							
								
							 | 
							fnbrfvb | 
							⊢ ( ( 𝐹  Fn  dom  𝐹  ∧  𝐴  ∈  dom  𝐹 )  →  ( ( 𝐹 ‘ 𝐴 )  =  𝐵  ↔  𝐴 𝐹 𝐵 ) )  | 
						
						
							| 3 | 
							
								1 2
							 | 
							sylanb | 
							⊢ ( ( Fun  𝐹  ∧  𝐴  ∈  dom  𝐹 )  →  ( ( 𝐹 ‘ 𝐴 )  =  𝐵  ↔  𝐴 𝐹 𝐵 ) )  |