Metamath Proof Explorer
Description: Equality deduction for nested function and operation value.
(Contributed by AV, 23-Jul-2022)
|
|
Ref |
Expression |
|
Hypothesis |
fvoveq1d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
|
Assertion |
fvoveq1d |
⊢ ( 𝜑 → ( 𝐹 ‘ ( 𝐴 𝑂 𝐶 ) ) = ( 𝐹 ‘ ( 𝐵 𝑂 𝐶 ) ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
fvoveq1d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
2 |
1
|
oveq1d |
⊢ ( 𝜑 → ( 𝐴 𝑂 𝐶 ) = ( 𝐵 𝑂 𝐶 ) ) |
3 |
2
|
fveq2d |
⊢ ( 𝜑 → ( 𝐹 ‘ ( 𝐴 𝑂 𝐶 ) ) = ( 𝐹 ‘ ( 𝐵 𝑂 𝐶 ) ) ) |