Metamath Proof Explorer


Theorem fvoveq1d

Description: Equality deduction for nested function and operation value. (Contributed by AV, 23-Jul-2022)

Ref Expression
Hypothesis fvoveq1d.1 ⊢ φ → A = B
Assertion fvoveq1d ⊢ φ → F ⁡ A O C = F ⁡ B O C

Proof

Step Hyp Ref Expression
1 fvoveq1d.1 ⊢ φ → A = B
2 1 oveq1d ⊢ φ → A O C = B O C
3 2 fveq2d ⊢ φ → F ⁡ A O C = F ⁡ B O C