Theorem fvoveq1d

Description: Equality deduction for nested function and operation value. (Contributed by AV, 23-Jul-2022)

	Ref	Expression
Hypothesis	fvoveq1d.1	|- ( ph -> A = B )
Assertion	fvoveq1d	|- ( ph -> ( F ` ( A O C ) ) = ( F ` ( B O C ) ) )

Proof

Step	Hyp	Ref	Expression
1		fvoveq1d.1	|- ( ph -> A = B )
2	1	oveq1d	|- ( ph -> ( A O C ) = ( B O C ) )
3	2	fveq2d	|- ( ph -> ( F ` ( A O C ) ) = ( F ` ( B O C ) ) )