Metamath Proof Explorer
Description: The identity element of a group belongs to the group. (Contributed by Thierry Arnoux, 4-May-2026)
|
|
Ref |
Expression |
|
Hypotheses |
grpidcld.1 |
⊢ 𝐵 = ( Base ‘ 𝐺 ) |
|
|
grpidcld.2 |
⊢ 0 = ( 0g ‘ 𝐺 ) |
|
|
grpidcld.3 |
⊢ ( 𝜑 → 𝐺 ∈ Grp ) |
|
Assertion |
grpidcld |
⊢ ( 𝜑 → 0 ∈ 𝐵 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
grpidcld.1 |
⊢ 𝐵 = ( Base ‘ 𝐺 ) |
| 2 |
|
grpidcld.2 |
⊢ 0 = ( 0g ‘ 𝐺 ) |
| 3 |
|
grpidcld.3 |
⊢ ( 𝜑 → 𝐺 ∈ Grp ) |
| 4 |
1 2
|
grpidcl |
⊢ ( 𝐺 ∈ Grp → 0 ∈ 𝐵 ) |
| 5 |
3 4
|
syl |
⊢ ( 𝜑 → 0 ∈ 𝐵 ) |