Metamath Proof Explorer


Theorem gsumunsnf

Description: Append an element to a finite group sum, using bound-variable hypotheses instead of distinct variable conditions. (Contributed by Mario Carneiro, 19-Dec-2014) (Revised by Thierry Arnoux, 28-Mar-2018) (Proof shortened by AV, 11-Dec-2019)

Ref Expression
Hypotheses gsumunsnf.0 ⊢ Ⅎ 𝑘 𝑌
gsumunsnf.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
gsumunsnf.p ⊢ + = ( +g ‘ 𝐺 )
gsumunsnf.g ⊢ ( 𝜑 → 𝐺 ∈ CMnd )
gsumunsnf.a ⊢ ( 𝜑 → 𝐴 ∈ Fin )
gsumunsnf.f ⊢ ( ( 𝜑 ∧ 𝑘 ∈ 𝐴 ) → 𝑋 ∈ 𝐵 )
gsumunsnf.m ⊢ ( 𝜑 → 𝑀 ∈ 𝑉 )
gsumunsnf.d ⊢ ( 𝜑 → ¬ 𝑀 ∈ 𝐴 )
gsumunsnf.y ⊢ ( 𝜑 → 𝑌 ∈ 𝐵 )
gsumunsnf.s ⊢ ( 𝑘 = 𝑀 → 𝑋 = 𝑌 )
Assertion gsumunsnf ( 𝜑 → ( 𝐺 Σg ( 𝑘 ∈ ( 𝐴 ∪ { 𝑀 } ) ↦ 𝑋 ) ) = ( ( 𝐺 Σg ( 𝑘 ∈ 𝐴 ↦ 𝑋 ) ) + 𝑌 ) )

Proof

Step Hyp Ref Expression
1 gsumunsnf.0 ⊢ Ⅎ 𝑘 𝑌
2 gsumunsnf.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
3 gsumunsnf.p ⊢ + = ( +g ‘ 𝐺 )
4 gsumunsnf.g ⊢ ( 𝜑 → 𝐺 ∈ CMnd )
5 gsumunsnf.a ⊢ ( 𝜑 → 𝐴 ∈ Fin )
6 gsumunsnf.f ⊢ ( ( 𝜑 ∧ 𝑘 ∈ 𝐴 ) → 𝑋 ∈ 𝐵 )
7 gsumunsnf.m ⊢ ( 𝜑 → 𝑀 ∈ 𝑉 )
8 gsumunsnf.d ⊢ ( 𝜑 → ¬ 𝑀 ∈ 𝐴 )
9 gsumunsnf.y ⊢ ( 𝜑 → 𝑌 ∈ 𝐵 )
10 gsumunsnf.s ⊢ ( 𝑘 = 𝑀 → 𝑋 = 𝑌 )
11 10 adantl ⊢ ( ( 𝜑 ∧ 𝑘 = 𝑀 ) → 𝑋 = 𝑌 )
12 2 3 4 5 6 7 8 9 11 1 gsumunsnfd ⊢ ( 𝜑 → ( 𝐺 Σg ( 𝑘 ∈ ( 𝐴 ∪ { 𝑀 } ) ↦ 𝑋 ) ) = ( ( 𝐺 Σg ( 𝑘 ∈ 𝐴 ↦ 𝑋 ) ) + 𝑌 ) )