Metamath Proof Explorer


Theorem halfcld

Description: Closure of half of a number (frequently used special case). (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypothesis 2timesd.1 ( 𝜑𝐴 ∈ ℂ )
Assertion halfcld ( 𝜑 → ( 𝐴 / 2 ) ∈ ℂ )

Proof

Step Hyp Ref Expression
1 2timesd.1 ( 𝜑𝐴 ∈ ℂ )
2 halfcl ( 𝐴 ∈ ℂ → ( 𝐴 / 2 ) ∈ ℂ )
3 1 2 syl ( 𝜑 → ( 𝐴 / 2 ) ∈ ℂ )