Metamath Proof Explorer


Theorem hfxp

Description: The Cartesian product of two hereditarily finite sets is a hereditarily finite set. (Contributed by Eric Schmidt, 26-Sep-2026)

Ref Expression
Assertion hfxp ( ( 𝐴 ∈ HF ∧ 𝐵 ∈ HF ) → ( 𝐴 × 𝐵 ) ∈ HF )

Proof

Step Hyp Ref Expression
1 hfun ⊢ ( ( 𝐴 ∈ HF ∧ 𝐵 ∈ HF ) → ( 𝐴 ∪ 𝐵 ) ∈ HF )
2 hfpw ⊢ ( ( 𝐴 ∪ 𝐵 ) ∈ HF → 𝒫 ( 𝐴 ∪ 𝐵 ) ∈ HF )
3 hfpw ⊢ ( 𝒫 ( 𝐴 ∪ 𝐵 ) ∈ HF → 𝒫 𝒫 ( 𝐴 ∪ 𝐵 ) ∈ HF )
4 xpsspw ⊢ ( 𝐴 × 𝐵 ) ⊆ 𝒫 𝒫 ( 𝐴 ∪ 𝐵 )
5 hfsshf ⊢ ( ( ( 𝐴 × 𝐵 ) ⊆ 𝒫 𝒫 ( 𝐴 ∪ 𝐵 ) ∧ 𝒫 𝒫 ( 𝐴 ∪ 𝐵 ) ∈ HF ) → ( 𝐴 × 𝐵 ) ∈ HF )
6 4 5 mpan ⊢ ( 𝒫 𝒫 ( 𝐴 ∪ 𝐵 ) ∈ HF → ( 𝐴 × 𝐵 ) ∈ HF )
7 1 2 3 6 4syl ⊢ ( ( 𝐴 ∈ HF ∧ 𝐵 ∈ HF ) → ( 𝐴 × 𝐵 ) ∈ HF )