Metamath Proof Explorer


Theorem hlcgreq

Description: A constructed point on a half-line, at a given distance of its origin, (see hlcgrex ) is unique. Theorem 6.11 of Schwabhauser p. 44. (Contributed by Thierry Arnoux, 9-Aug-2020)

Ref Expression
Hypotheses hlcgreq.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
hlcgreq.i ⊢ − = ( dist ‘ 𝐺 )
hlcgreq.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
hlcgreq.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
hlcgreq.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
hlcgreq.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
hlcgreq.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
hlcgreq.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
hlcgreq.1 ⊢ ( 𝜑 → 𝐷 ≠ 𝐴 )
hlcgreq.2 ⊢ ( 𝜑 → 𝐵 ≠ 𝐶 )
hlcgreq.3 ⊢ ( 𝜑 → 𝑋 ( 𝐾 ‘ 𝐴 ) 𝐷 )
hlcgreq.4 ⊢ ( 𝜑 → 𝑌 ( 𝐾 ‘ 𝐴 ) 𝐷 )
hlcgreq.5 ⊢ ( 𝜑 → ( 𝐴 − 𝑋 ) = ( 𝐵 − 𝐶 ) )
hlcgreq.6 ⊢ ( 𝜑 → ( 𝐴 − 𝑌 ) = ( 𝐵 − 𝐶 ) )
Assertion hlcgreq ( 𝜑 → 𝑋 = 𝑌 )

Proof

Step Hyp Ref Expression
1 hlcgreq.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 hlcgreq.i ⊢ − = ( dist ‘ 𝐺 )
3 hlcgreq.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
4 hlcgreq.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
5 hlcgreq.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
6 hlcgreq.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
7 hlcgreq.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
8 hlcgreq.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
9 hlcgreq.1 ⊢ ( 𝜑 → 𝐷 ≠ 𝐴 )
10 hlcgreq.2 ⊢ ( 𝜑 → 𝐵 ≠ 𝐶 )
11 hlcgreq.3 ⊢ ( 𝜑 → 𝑋 ( 𝐾 ‘ 𝐴 ) 𝐷 )
12 hlcgreq.4 ⊢ ( 𝜑 → 𝑌 ( 𝐾 ‘ 𝐴 ) 𝐷 )
13 hlcgreq.5 ⊢ ( 𝜑 → ( 𝐴 − 𝑋 ) = ( 𝐵 − 𝐶 ) )
14 hlcgreq.6 ⊢ ( 𝜑 → ( 𝐴 − 𝑌 ) = ( 𝐵 − 𝐶 ) )
15 eqid ⊢ ( Itv ‘ 𝐺 ) = ( Itv ‘ 𝐺 )
16 1 15 3 7 4 11 hlgrcl1 ⊢ ( 𝜑 → 𝑋 ∈ 𝑃 )
17 1 15 3 7 4 12 hlgrcl1 ⊢ ( 𝜑 → 𝑌 ∈ 𝑃 )
18 1 15 3 4 5 6 7 8 2 9 10 16 17 11 12 13 14 hlcgreulem ⊢ ( 𝜑 → 𝑋 = 𝑌 )