Metamath Proof Explorer


Theorem idressidex

Description: The restriction of a structure with an identity element to a subset containing the identity element has an identity element. (Contributed by Jeff Madsen, 8-Jun-2010) (Revised by Mario Carneiro, 23-Dec-2013) (Revised by AV, 11-Aug-2026)

Ref Expression
Hypotheses idressidex.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
idressidex.p ⊢ + = ( +g ‘ 𝐺 )
idressidex.o ⊢ 0 = ( 0g ‘ 𝐺 )
idressidex.e ⊢ ( 𝜑 → ∃ 𝑒 ∈ 𝐵 ∀ 𝑥 ∈ 𝐵 ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) )
idressidex.s ⊢ 𝑆 = ( 𝐺 ↾s 𝐴 )
idressidex.a ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
idressidex.0 ⊢ ( 𝜑 → 0 ∈ 𝐴 )
Assertion idressidex ( 𝜑 → ∃ 𝑒 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) )

Proof

Step Hyp Ref Expression
1 idressidex.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
2 idressidex.p ⊢ + = ( +g ‘ 𝐺 )
3 idressidex.o ⊢ 0 = ( 0g ‘ 𝐺 )
4 idressidex.e ⊢ ( 𝜑 → ∃ 𝑒 ∈ 𝐵 ∀ 𝑥 ∈ 𝐵 ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) )
5 idressidex.s ⊢ 𝑆 = ( 𝐺 ↾s 𝐴 )
6 idressidex.a ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
7 idressidex.0 ⊢ ( 𝜑 → 0 ∈ 𝐴 )
8 eqid ⊢ ( Base ‘ 𝑆 ) = ( Base ‘ 𝑆 )
9 1 2 3 4 5 6 7 8 idressidex0 ⊢ ( 𝜑 → ∃ 𝑒 ∈ ( Base ‘ 𝑆 ) ∀ 𝑥 ∈ ( Base ‘ 𝑆 ) ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) )
10 5 1 ressbas2 ⊢ ( 𝐴 ⊆ 𝐵 → 𝐴 = ( Base ‘ 𝑆 ) )
11 id ⊢ ( 𝐴 = ( Base ‘ 𝑆 ) → 𝐴 = ( Base ‘ 𝑆 ) )
12 raleq ⊢ ( 𝐴 = ( Base ‘ 𝑆 ) → ( ∀ 𝑥 ∈ 𝐴 ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) ↔ ∀ 𝑥 ∈ ( Base ‘ 𝑆 ) ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) ) )
13 11 12 rexeqbidv ⊢ ( 𝐴 = ( Base ‘ 𝑆 ) → ( ∃ 𝑒 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) ↔ ∃ 𝑒 ∈ ( Base ‘ 𝑆 ) ∀ 𝑥 ∈ ( Base ‘ 𝑆 ) ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) ) )
14 6 10 13 3syl ⊢ ( 𝜑 → ( ∃ 𝑒 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) ↔ ∃ 𝑒 ∈ ( Base ‘ 𝑆 ) ∀ 𝑥 ∈ ( Base ‘ 𝑆 ) ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) ) )
15 9 14 mpbird ⊢ ( 𝜑 → ∃ 𝑒 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( ( 𝑒 + 𝑥 ) = 𝑥 ∧ ( 𝑥 + 𝑒 ) = 𝑥 ) )