Metamath Proof Explorer


Theorem iinuni

Description: A relationship involving union and indexed intersection. Exercise 23 of Enderton p. 33. (Contributed by NM, 25-Nov-2003) (Proof shortened by Mario Carneiro, 17-Nov-2016)

Ref Expression
Assertion iinuni ( 𝐴 ∪ ∩ 𝐵 ) = ∩ 𝑥 ∈ 𝐵 ( 𝐴 ∪ 𝑥 )

Proof

Step Hyp Ref Expression
1 r19.32v ⊢ ( ∀ 𝑥 ∈ 𝐵 ( 𝑦 ∈ 𝐴 ∨ 𝑦 ∈ 𝑥 ) ↔ ( 𝑦 ∈ 𝐴 ∨ ∀ 𝑥 ∈ 𝐵 𝑦 ∈ 𝑥 ) )
2 elun ⊢ ( 𝑦 ∈ ( 𝐴 ∪ 𝑥 ) ↔ ( 𝑦 ∈ 𝐴 ∨ 𝑦 ∈ 𝑥 ) )
3 2 ralbii ⊢ ( ∀ 𝑥 ∈ 𝐵 𝑦 ∈ ( 𝐴 ∪ 𝑥 ) ↔ ∀ 𝑥 ∈ 𝐵 ( 𝑦 ∈ 𝐴 ∨ 𝑦 ∈ 𝑥 ) )
4 vex ⊢ 𝑦 ∈ V
5 4 elint2 ⊢ ( 𝑦 ∈ ∩ 𝐵 ↔ ∀ 𝑥 ∈ 𝐵 𝑦 ∈ 𝑥 )
6 5 orbi2i ⊢ ( ( 𝑦 ∈ 𝐴 ∨ 𝑦 ∈ ∩ 𝐵 ) ↔ ( 𝑦 ∈ 𝐴 ∨ ∀ 𝑥 ∈ 𝐵 𝑦 ∈ 𝑥 ) )
7 1 3 6 3bitr4ri ⊢ ( ( 𝑦 ∈ 𝐴 ∨ 𝑦 ∈ ∩ 𝐵 ) ↔ ∀ 𝑥 ∈ 𝐵 𝑦 ∈ ( 𝐴 ∪ 𝑥 ) )
8 7 abbii ⊢ { 𝑦 ∣ ( 𝑦 ∈ 𝐴 ∨ 𝑦 ∈ ∩ 𝐵 ) } = { 𝑦 ∣ ∀ 𝑥 ∈ 𝐵 𝑦 ∈ ( 𝐴 ∪ 𝑥 ) }
9 df-un ⊢ ( 𝐴 ∪ ∩ 𝐵 ) = { 𝑦 ∣ ( 𝑦 ∈ 𝐴 ∨ 𝑦 ∈ ∩ 𝐵 ) }
10 df-iin ⊢ ∩ 𝑥 ∈ 𝐵 ( 𝐴 ∪ 𝑥 ) = { 𝑦 ∣ ∀ 𝑥 ∈ 𝐵 𝑦 ∈ ( 𝐴 ∪ 𝑥 ) }
11 8 9 10 3eqtr4i ⊢ ( 𝐴 ∪ ∩ 𝐵 ) = ∩ 𝑥 ∈ 𝐵 ( 𝐴 ∪ 𝑥 )