Metamath Proof Explorer


Theorem imadisj

Description: A class whose image under another is empty is disjoint with the other's domain. (Contributed by FL, 24-Jan-2007)

Ref Expression
Assertion imadisj ( ( 𝐴𝐵 ) = ∅ ↔ ( dom 𝐴𝐵 ) = ∅ )

Proof

Step Hyp Ref Expression
1 df-ima ( 𝐴𝐵 ) = ran ( 𝐴𝐵 )
2 1 eqeq1i ( ( 𝐴𝐵 ) = ∅ ↔ ran ( 𝐴𝐵 ) = ∅ )
3 dm0rn0 ( dom ( 𝐴𝐵 ) = ∅ ↔ ran ( 𝐴𝐵 ) = ∅ )
4 dmres dom ( 𝐴𝐵 ) = ( 𝐵 ∩ dom 𝐴 )
5 incom ( 𝐵 ∩ dom 𝐴 ) = ( dom 𝐴𝐵 )
6 4 5 eqtri dom ( 𝐴𝐵 ) = ( dom 𝐴𝐵 )
7 6 eqeq1i ( dom ( 𝐴𝐵 ) = ∅ ↔ ( dom 𝐴𝐵 ) = ∅ )
8 2 3 7 3bitr2i ( ( 𝐴𝐵 ) = ∅ ↔ ( dom 𝐴𝐵 ) = ∅ )