Metamath Proof Explorer


Theorem ineqcomi

Description: Disjointness inference (when C = (/) ), inference form of ineqcom . (Contributed by Peter Mazsa, 26-Mar-2017)

Ref Expression
Hypothesis ineqcomi.1 ( 𝐴𝐵 ) = 𝐶
Assertion ineqcomi ( 𝐵𝐴 ) = 𝐶

Proof

Step Hyp Ref Expression
1 ineqcomi.1 ( 𝐴𝐵 ) = 𝐶
2 ineqcom ( ( 𝐴𝐵 ) = 𝐶 ↔ ( 𝐵𝐴 ) = 𝐶 )
3 1 2 mpbi ( 𝐵𝐴 ) = 𝐶