Metamath Proof Explorer


Theorem ineqcomi

Description: Disjointness inference (when C = (/) ), inference form of ineqcom . (Contributed by Peter Mazsa, 26-Mar-2017)

Ref Expression
Hypothesis ineqcomi.1
|- ( A i^i B ) = C
Assertion ineqcomi
|- ( B i^i A ) = C

Proof

Step Hyp Ref Expression
1 ineqcomi.1
 |-  ( A i^i B ) = C
2 ineqcom
 |-  ( ( A i^i B ) = C <-> ( B i^i A ) = C )
3 1 2 mpbi
 |-  ( B i^i A ) = C