Metamath Proof Explorer


Theorem ineqcomi

Description: Two ways of expressing that two classes have a given intersection. Inference form of ineqcom . Disjointness inference when C = (/) . (Contributed by Peter Mazsa, 26-Mar-2017) (Proof shortened by SN, 20-Sep-2024)

Ref Expression
Hypothesis ineqcomi.1 ⊢ A ∩ B = C
Assertion ineqcomi ⊢ B ∩ A = C

Proof

Step Hyp Ref Expression
1 ineqcomi.1 ⊢ A ∩ B = C
2 incom ⊢ B ∩ A = A ∩ B
3 2 1 eqtri ⊢ B ∩ A = C