Metamath Proof Explorer


Theorem int-eqineqd

Description: EquivalenceImpliesDoubleInequality generator rule. (Contributed by Stanislas Polu, 7-Apr-2020)

Ref Expression
Hypotheses int-eqineqd.1 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
int-eqineqd.2 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion int-eqineqd ( 𝜑 → 𝐵 ≤ 𝐴 )

Proof

Step Hyp Ref Expression
1 int-eqineqd.1 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
2 int-eqineqd.2 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
3 2 eqcomd ⊢ ( 𝜑 → 𝐵 = 𝐴 )
4 1 3 eqled ⊢ ( 𝜑 → 𝐵 ≤ 𝐴 )