Theorem int-eqineqd

Description: EquivalenceImpliesDoubleInequality generator rule. (Contributed by Stanislas Polu, 7-Apr-2020)

	Ref	Expression
Hypotheses	int-eqineqd.1	|- ( ph -> B e. RR )
	int-eqineqd.2	|- ( ph -> A = B )
Assertion	int-eqineqd	|- ( ph -> B <_ A )

Proof

Step	Hyp	Ref	Expression
1		int-eqineqd.1	|- ( ph -> B e. RR )
2		int-eqineqd.2	|- ( ph -> A = B )
3	2	eqcomd	|- ( ph -> B = A )
4	1 3	eqled	|- ( ph -> B <_ A )