Metamath Proof Explorer


Theorem intidg

Description: The intersection of all sets to which a set belongs is the singleton of that set. (Contributed by NM, 5-Jun-2009) Put in closed form and avoid ax-nul . (Revised by BJ, 17-Jan-2025)

Ref Expression
Assertion intidg ( 𝐴 ∈ 𝑉 → ∩ { 𝑥 ∣ 𝐴 ∈ 𝑥 } = { 𝐴 } )

Proof

Step Hyp Ref Expression
1 snexg ⊢ ( 𝐴 ∈ 𝑉 → { 𝐴 } ∈ V )
2 snidg ⊢ ( 𝐴 ∈ 𝑉 → 𝐴 ∈ { 𝐴 } )
3 eleq2 ⊢ ( 𝑥 = { 𝐴 } → ( 𝐴 ∈ 𝑥 ↔ 𝐴 ∈ { 𝐴 } ) )
4 1 2 3 elabd ⊢ ( 𝐴 ∈ 𝑉 → { 𝐴 } ∈ { 𝑥 ∣ 𝐴 ∈ 𝑥 } )
5 intss1 ⊢ ( { 𝐴 } ∈ { 𝑥 ∣ 𝐴 ∈ 𝑥 } → ∩ { 𝑥 ∣ 𝐴 ∈ 𝑥 } ⊆ { 𝐴 } )
6 4 5 syl ⊢ ( 𝐴 ∈ 𝑉 → ∩ { 𝑥 ∣ 𝐴 ∈ 𝑥 } ⊆ { 𝐴 } )
7 id ⊢ ( 𝐴 ∈ 𝑥 → 𝐴 ∈ 𝑥 )
8 7 ax-gen ⊢ ∀ 𝑥 ( 𝐴 ∈ 𝑥 → 𝐴 ∈ 𝑥 )
9 elintabg ⊢ ( 𝐴 ∈ 𝑉 → ( 𝐴 ∈ ∩ { 𝑥 ∣ 𝐴 ∈ 𝑥 } ↔ ∀ 𝑥 ( 𝐴 ∈ 𝑥 → 𝐴 ∈ 𝑥 ) ) )
10 8 9 mpbiri ⊢ ( 𝐴 ∈ 𝑉 → 𝐴 ∈ ∩ { 𝑥 ∣ 𝐴 ∈ 𝑥 } )
11 10 snssd ⊢ ( 𝐴 ∈ 𝑉 → { 𝐴 } ⊆ ∩ { 𝑥 ∣ 𝐴 ∈ 𝑥 } )
12 6 11 eqssd ⊢ ( 𝐴 ∈ 𝑉 → ∩ { 𝑥 ∣ 𝐴 ∈ 𝑥 } = { 𝐴 } )