Metamath Proof Explorer


Theorem ipolub0

Description: The LUB of the empty set is the intersection of the base. (Contributed by Zhi Wang, 30-Sep-2024)

Ref Expression
Hypotheses ipoglb0.i ⊢ 𝐼 = ( toInc ‘ 𝐹 )
ipolub0.u ⊢ ( 𝜑 → 𝑈 = ( lub ‘ 𝐼 ) )
ipolub0.f ⊢ ( 𝜑 → ∩ 𝐹 ∈ 𝐹 )
ipolub0.v ⊢ ( 𝜑 → 𝐹 ∈ 𝑉 )
Assertion ipolub0 ( 𝜑 → ( 𝑈 ‘ ∅ ) = ∩ 𝐹 )

Proof

Step Hyp Ref Expression
1 ipoglb0.i ⊢ 𝐼 = ( toInc ‘ 𝐹 )
2 ipolub0.u ⊢ ( 𝜑 → 𝑈 = ( lub ‘ 𝐼 ) )
3 ipolub0.f ⊢ ( 𝜑 → ∩ 𝐹 ∈ 𝐹 )
4 ipolub0.v ⊢ ( 𝜑 → 𝐹 ∈ 𝑉 )
5 0ss ⊢ ∅ ⊆ 𝐹
6 5 a1i ⊢ ( 𝜑 → ∅ ⊆ 𝐹 )
7 uni0 ⊢ ∪ ∅ = ∅
8 0ss ⊢ ∅ ⊆ 𝑥
9 7 8 eqsstri ⊢ ∪ ∅ ⊆ 𝑥
10 9 a1i ⊢ ( 𝑥 ∈ 𝐹 → ∪ ∅ ⊆ 𝑥 )
11 10 rabeqc ⊢ { 𝑥 ∈ 𝐹 ∣ ∪ ∅ ⊆ 𝑥 } = 𝐹
12 11 eqcomi ⊢ 𝐹 = { 𝑥 ∈ 𝐹 ∣ ∪ ∅ ⊆ 𝑥 }
13 12 inteqi ⊢ ∩ 𝐹 = ∩ { 𝑥 ∈ 𝐹 ∣ ∪ ∅ ⊆ 𝑥 }
14 13 a1i ⊢ ( 𝜑 → ∩ 𝐹 = ∩ { 𝑥 ∈ 𝐹 ∣ ∪ ∅ ⊆ 𝑥 } )
15 1 4 6 2 14 3 ipolub ⊢ ( 𝜑 → ( 𝑈 ‘ ∅ ) = ∩ 𝐹 )