Metamath Proof Explorer


Theorem isat

Description: The predicate "is an atom". ( ela analog.) (Contributed by NM, 18-Sep-2011)

Ref Expression
Hypotheses isatom.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
isatom.z ⊢ 0 = ( 0. ‘ 𝐾 )
isatom.c ⊢ 𝐶 = ( ⋖ ‘ 𝐾 )
isatom.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
Assertion isat ( 𝐾 ∈ 𝐷 → ( 𝑃 ∈ 𝐴 ↔ ( 𝑃 ∈ 𝐵 ∧ 0 𝐶 𝑃 ) ) )

Proof

Step Hyp Ref Expression
1 isatom.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
2 isatom.z ⊢ 0 = ( 0. ‘ 𝐾 )
3 isatom.c ⊢ 𝐶 = ( ⋖ ‘ 𝐾 )
4 isatom.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
5 1 2 3 4 pats ⊢ ( 𝐾 ∈ 𝐷 → 𝐴 = { 𝑥 ∈ 𝐵 ∣ 0 𝐶 𝑥 } )
6 5 eleq2d ⊢ ( 𝐾 ∈ 𝐷 → ( 𝑃 ∈ 𝐴 ↔ 𝑃 ∈ { 𝑥 ∈ 𝐵 ∣ 0 𝐶 𝑥 } ) )
7 breq2 ⊢ ( 𝑥 = 𝑃 → ( 0 𝐶 𝑥 ↔ 0 𝐶 𝑃 ) )
8 7 elrab ⊢ ( 𝑃 ∈ { 𝑥 ∈ 𝐵 ∣ 0 𝐶 𝑥 } ↔ ( 𝑃 ∈ 𝐵 ∧ 0 𝐶 𝑃 ) )
9 6 8 bitrdi ⊢ ( 𝐾 ∈ 𝐷 → ( 𝑃 ∈ 𝐴 ↔ ( 𝑃 ∈ 𝐵 ∧ 0 𝐶 𝑃 ) ) )