Metamath Proof Explorer


Theorem iscmn

Description: The predicate "is a commutative monoid." (Contributed by Mario Carneiro, 6-Jan-2015)

Ref Expression
Hypotheses iscmn.b 𝐵 = ( Base ‘ 𝐺 )
iscmn.p + = ( +g𝐺 )
Assertion iscmn ( 𝐺 ∈ CMnd ↔ ( 𝐺 ∈ Mnd ∧ ∀ 𝑥𝐵𝑦𝐵 ( 𝑥 + 𝑦 ) = ( 𝑦 + 𝑥 ) ) )

Proof

Step Hyp Ref Expression
1 iscmn.b 𝐵 = ( Base ‘ 𝐺 )
2 iscmn.p + = ( +g𝐺 )
3 fveq2 ( 𝑔 = 𝐺 → ( Base ‘ 𝑔 ) = ( Base ‘ 𝐺 ) )
4 3 1 eqtr4di ( 𝑔 = 𝐺 → ( Base ‘ 𝑔 ) = 𝐵 )
5 raleq ( ( Base ‘ 𝑔 ) = 𝐵 → ( ∀ 𝑦 ∈ ( Base ‘ 𝑔 ) ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ↔ ∀ 𝑦𝐵 ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ) )
6 5 raleqbi1dv ( ( Base ‘ 𝑔 ) = 𝐵 → ( ∀ 𝑥 ∈ ( Base ‘ 𝑔 ) ∀ 𝑦 ∈ ( Base ‘ 𝑔 ) ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ↔ ∀ 𝑥𝐵𝑦𝐵 ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ) )
7 4 6 syl ( 𝑔 = 𝐺 → ( ∀ 𝑥 ∈ ( Base ‘ 𝑔 ) ∀ 𝑦 ∈ ( Base ‘ 𝑔 ) ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ↔ ∀ 𝑥𝐵𝑦𝐵 ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ) )
8 fveq2 ( 𝑔 = 𝐺 → ( +g𝑔 ) = ( +g𝐺 ) )
9 8 2 eqtr4di ( 𝑔 = 𝐺 → ( +g𝑔 ) = + )
10 9 oveqd ( 𝑔 = 𝐺 → ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑥 + 𝑦 ) )
11 9 oveqd ( 𝑔 = 𝐺 → ( 𝑦 ( +g𝑔 ) 𝑥 ) = ( 𝑦 + 𝑥 ) )
12 10 11 eqeq12d ( 𝑔 = 𝐺 → ( ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ↔ ( 𝑥 + 𝑦 ) = ( 𝑦 + 𝑥 ) ) )
13 12 2ralbidv ( 𝑔 = 𝐺 → ( ∀ 𝑥𝐵𝑦𝐵 ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ↔ ∀ 𝑥𝐵𝑦𝐵 ( 𝑥 + 𝑦 ) = ( 𝑦 + 𝑥 ) ) )
14 7 13 bitrd ( 𝑔 = 𝐺 → ( ∀ 𝑥 ∈ ( Base ‘ 𝑔 ) ∀ 𝑦 ∈ ( Base ‘ 𝑔 ) ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) ↔ ∀ 𝑥𝐵𝑦𝐵 ( 𝑥 + 𝑦 ) = ( 𝑦 + 𝑥 ) ) )
15 df-cmn CMnd = { 𝑔 ∈ Mnd ∣ ∀ 𝑥 ∈ ( Base ‘ 𝑔 ) ∀ 𝑦 ∈ ( Base ‘ 𝑔 ) ( 𝑥 ( +g𝑔 ) 𝑦 ) = ( 𝑦 ( +g𝑔 ) 𝑥 ) }
16 14 15 elrab2 ( 𝐺 ∈ CMnd ↔ ( 𝐺 ∈ Mnd ∧ ∀ 𝑥𝐵𝑦𝐵 ( 𝑥 + 𝑦 ) = ( 𝑦 + 𝑥 ) ) )