Metamath Proof Explorer


Theorem isfld

Description: A field is a commutative division ring. (Contributed by Mario Carneiro, 17-Jun-2015)

Ref Expression
Assertion isfld ( 𝑅 ∈ Field ↔ ( 𝑅 ∈ DivRing ∧ 𝑅 ∈ CRing ) )

Proof

Step Hyp Ref Expression
1 df-field Field = ( DivRing ∩ CRing )
2 1 elin2 ( 𝑅 ∈ Field ↔ ( 𝑅 ∈ DivRing ∧ 𝑅 ∈ CRing ) )