Metamath Proof Explorer


Theorem flddrngd

Description: A field is a division ring. (Contributed by Jeff Madsen, 10-Jun-2010) (Revised by SN, 17-Jan-2025)

Ref Expression
Hypothesis flddrngd.1 ⊢ ( 𝜑 → 𝑅 ∈ Field )
Assertion flddrngd ( 𝜑 → 𝑅 ∈ DivRing )

Proof

Step Hyp Ref Expression
1 flddrngd.1 ⊢ ( 𝜑 → 𝑅 ∈ Field )
2 isfld ⊢ ( 𝑅 ∈ Field ↔ ( 𝑅 ∈ DivRing ∧ 𝑅 ∈ CRing ) )
3 2 simplbi ⊢ ( 𝑅 ∈ Field → 𝑅 ∈ DivRing )
4 1 3 syl ⊢ ( 𝜑 → 𝑅 ∈ DivRing )