Metamath Proof Explorer


Theorem fldcrngd

Description: A field is a commutative ring. (Contributed by Jeff Madsen, 8-Jun-2010) (Revised by SN, 23-Nov-2024)

Ref Expression
Hypothesis fldcrngd.1 ⊢ ( 𝜑 → 𝑅 ∈ Field )
Assertion fldcrngd ( 𝜑 → 𝑅 ∈ CRing )

Proof

Step Hyp Ref Expression
1 fldcrngd.1 ⊢ ( 𝜑 → 𝑅 ∈ Field )
2 isfld ⊢ ( 𝑅 ∈ Field ↔ ( 𝑅 ∈ DivRing ∧ 𝑅 ∈ CRing ) )
3 2 simprbi ⊢ ( 𝑅 ∈ Field → 𝑅 ∈ CRing )
4 1 3 syl ⊢ ( 𝜑 → 𝑅 ∈ CRing )