Metamath Proof Explorer


Theorem fldcrngd

Description: A field is a commutative ring. EDITORIAL: Shortens recrng . Also recrng should be named resrng. Also fldcrng is misnamed. (Contributed by SN, 23-Nov-2024)

Ref Expression
Hypothesis fldcrngd.1 ( 𝜑𝑅 ∈ Field )
Assertion fldcrngd ( 𝜑𝑅 ∈ CRing )

Proof

Step Hyp Ref Expression
1 fldcrngd.1 ( 𝜑𝑅 ∈ Field )
2 isfld ( 𝑅 ∈ Field ↔ ( 𝑅 ∈ DivRing ∧ 𝑅 ∈ CRing ) )
3 2 simprbi ( 𝑅 ∈ Field → 𝑅 ∈ CRing )
4 1 3 syl ( 𝜑𝑅 ∈ CRing )