Metamath Proof Explorer


Theorem fldcrngd

Description: A field is a commutative ring. (Contributed by Jeff Madsen, 8-Jun-2010) (Revised by SN, 23-Nov-2024)

Ref Expression
Hypothesis fldcrngd.1 ⊢ φ → R ∈ Field
Assertion fldcrngd ⊢ φ → R ∈ CRing

Proof

Step Hyp Ref Expression
1 fldcrngd.1 ⊢ φ → R ∈ Field
2 isfld ⊢ R ∈ Field ↔ R ∈ DivRing ∧ R ∈ CRing
3 2 simprbi ⊢ R ∈ Field → R ∈ CRing
4 1 3 syl ⊢ φ → R ∈ CRing