Metamath Proof Explorer


Theorem flddrngd

Description: A field is a division ring. (Contributed by Jeff Madsen, 10-Jun-2010) (Revised by SN, 17-Jan-2025)

Ref Expression
Hypothesis flddrngd.1 ⊢ φ → R ∈ Field
Assertion flddrngd ⊢ φ → R ∈ DivRing

Proof

Step Hyp Ref Expression
1 flddrngd.1 ⊢ φ → R ∈ Field
2 isfld ⊢ R ∈ Field ↔ R ∈ DivRing ∧ R ∈ CRing
3 2 simplbi ⊢ R ∈ Field → R ∈ DivRing
4 1 3 syl ⊢ φ → R ∈ DivRing