Metamath Proof Explorer


Theorem isnzr

Description: Property of a nonzero ring. (Contributed by Stefan O'Rear, 24-Feb-2015)

Ref Expression
Hypotheses isnzr.o ⊢ 1 = ( 1r ‘ 𝑅 )
isnzr.z ⊢ 0 = ( 0g ‘ 𝑅 )
Assertion isnzr ( 𝑅 ∈ NzRing ↔ ( 𝑅 ∈ Ring ∧ 1 ≠ 0 ) )

Proof

Step Hyp Ref Expression
1 isnzr.o ⊢ 1 = ( 1r ‘ 𝑅 )
2 isnzr.z ⊢ 0 = ( 0g ‘ 𝑅 )
3 fveq2 ⊢ ( 𝑟 = 𝑅 → ( 1r ‘ 𝑟 ) = ( 1r ‘ 𝑅 ) )
4 3 1 eqtr4di ⊢ ( 𝑟 = 𝑅 → ( 1r ‘ 𝑟 ) = 1 )
5 fveq2 ⊢ ( 𝑟 = 𝑅 → ( 0g ‘ 𝑟 ) = ( 0g ‘ 𝑅 ) )
6 5 2 eqtr4di ⊢ ( 𝑟 = 𝑅 → ( 0g ‘ 𝑟 ) = 0 )
7 4 6 neeq12d ⊢ ( 𝑟 = 𝑅 → ( ( 1r ‘ 𝑟 ) ≠ ( 0g ‘ 𝑟 ) ↔ 1 ≠ 0 ) )
8 df-nzr ⊢ NzRing = { 𝑟 ∈ Ring ∣ ( 1r ‘ 𝑟 ) ≠ ( 0g ‘ 𝑟 ) }
9 7 8 elrab2 ⊢ ( 𝑅 ∈ NzRing ↔ ( 𝑅 ∈ Ring ∧ 1 ≠ 0 ) )