Metamath Proof Explorer


Theorem issetf

Description: A version of isset that does not require x and A to be distinct. (Contributed by Andrew Salmon, 6-Jun-2011) (Revised by Mario Carneiro, 10-Oct-2016)

Ref Expression
Hypothesis issetf.1 𝑥 𝐴
Assertion issetf ( 𝐴 ∈ V ↔ ∃ 𝑥 𝑥 = 𝐴 )

Proof

Step Hyp Ref Expression
1 issetf.1 𝑥 𝐴
2 isset ( 𝐴 ∈ V ↔ ∃ 𝑦 𝑦 = 𝐴 )
3 1 nfeq2 𝑥 𝑦 = 𝐴
4 nfv 𝑦 𝑥 = 𝐴
5 eqeq1 ( 𝑦 = 𝑥 → ( 𝑦 = 𝐴𝑥 = 𝐴 ) )
6 3 4 5 cbvexv1 ( ∃ 𝑦 𝑦 = 𝐴 ↔ ∃ 𝑥 𝑥 = 𝐴 )
7 2 6 bitri ( 𝐴 ∈ V ↔ ∃ 𝑥 𝑥 = 𝐴 )