Metamath Proof Explorer


Theorem istop2g

Description: Express the predicate " J is a topology" using nonempty finite intersections instead of binary intersections as in istopg . (Contributed by NM, 19-Jul-2006)

Ref Expression
Assertion istop2g ( 𝐽 ∈ 𝐴 → ( 𝐽 ∈ Top ↔ ( ∀ 𝑥 ( 𝑥 ⊆ 𝐽 → ∪ 𝑥 ∈ 𝐽 ) ∧ ∀ 𝑥 ( ( 𝑥 ⊆ 𝐽 ∧ 𝑥 ≠ ∅ ∧ 𝑥 ∈ Fin ) → ∩ 𝑥 ∈ 𝐽 ) ) ) )

Proof

Step Hyp Ref Expression
1 istopg ⊢ ( 𝐽 ∈ 𝐴 → ( 𝐽 ∈ Top ↔ ( ∀ 𝑥 ( 𝑥 ⊆ 𝐽 → ∪ 𝑥 ∈ 𝐽 ) ∧ ∀ 𝑥 ∈ 𝐽 ∀ 𝑦 ∈ 𝐽 ( 𝑥 ∩ 𝑦 ) ∈ 𝐽 ) ) )
2 fiint ⊢ ( ∀ 𝑥 ∈ 𝐽 ∀ 𝑦 ∈ 𝐽 ( 𝑥 ∩ 𝑦 ) ∈ 𝐽 ↔ ∀ 𝑥 ( ( 𝑥 ⊆ 𝐽 ∧ 𝑥 ≠ ∅ ∧ 𝑥 ∈ Fin ) → ∩ 𝑥 ∈ 𝐽 ) )
3 2 anbi2i ⊢ ( ( ∀ 𝑥 ( 𝑥 ⊆ 𝐽 → ∪ 𝑥 ∈ 𝐽 ) ∧ ∀ 𝑥 ∈ 𝐽 ∀ 𝑦 ∈ 𝐽 ( 𝑥 ∩ 𝑦 ) ∈ 𝐽 ) ↔ ( ∀ 𝑥 ( 𝑥 ⊆ 𝐽 → ∪ 𝑥 ∈ 𝐽 ) ∧ ∀ 𝑥 ( ( 𝑥 ⊆ 𝐽 ∧ 𝑥 ≠ ∅ ∧ 𝑥 ∈ Fin ) → ∩ 𝑥 ∈ 𝐽 ) ) )
4 1 3 bitrdi ⊢ ( 𝐽 ∈ 𝐴 → ( 𝐽 ∈ Top ↔ ( ∀ 𝑥 ( 𝑥 ⊆ 𝐽 → ∪ 𝑥 ∈ 𝐽 ) ∧ ∀ 𝑥 ( ( 𝑥 ⊆ 𝐽 ∧ 𝑥 ≠ ∅ ∧ 𝑥 ∈ Fin ) → ∩ 𝑥 ∈ 𝐽 ) ) ) )