Metamath Proof Explorer


Theorem iuneq2d

Description: Equality deduction for indexed union. (Contributed by Drahflow, 22-Oct-2015)

Ref Expression
Hypothesis iuneq2d.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
Assertion iuneq2d ( 𝜑 → ∪ 𝑥 ∈ 𝐴 𝐵 = ∪ 𝑥 ∈ 𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 iuneq2d.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
2 1 adantr ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 = 𝐶 )
3 2 iuneq2dv ⊢ ( 𝜑 → ∪ 𝑥 ∈ 𝐴 𝐵 = ∪ 𝑥 ∈ 𝐴 𝐶 )