Metamath Proof Explorer


Theorem iuneq2df

Description: Equality deduction for indexed union. (Contributed by Glauco Siliprandi, 17-Aug-2020)

Ref Expression
Hypotheses iuneq2df.1 ⊢ Ⅎ 𝑥 𝜑
iuneq2df.2 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 = 𝐶 )
Assertion iuneq2df ( 𝜑 → ∪ 𝑥 ∈ 𝐴 𝐵 = ∪ 𝑥 ∈ 𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 iuneq2df.1 ⊢ Ⅎ 𝑥 𝜑
2 iuneq2df.2 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 = 𝐶 )
3 2 ex ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 → 𝐵 = 𝐶 ) )
4 1 3 ralrimi ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 𝐵 = 𝐶 )
5 iuneq2 ⊢ ( ∀ 𝑥 ∈ 𝐴 𝐵 = 𝐶 → ∪ 𝑥 ∈ 𝐴 𝐵 = ∪ 𝑥 ∈ 𝐴 𝐶 )
6 4 5 syl ⊢ ( 𝜑 → ∪ 𝑥 ∈ 𝐴 𝐵 = ∪ 𝑥 ∈ 𝐴 𝐶 )