Metamath Proof Explorer


Theorem iunrab

Description: The indexed union of a restricted class abstraction. (Contributed by NM, 3-Jan-2004) (Proof shortened by Mario Carneiro, 14-Nov-2016)

Ref Expression
Assertion iunrab ∪ 𝑥 ∈ 𝐴 { 𝑦 ∈ 𝐵 ∣ 𝜑 } = { 𝑦 ∈ 𝐵 ∣ ∃ 𝑥 ∈ 𝐴 𝜑 }

Proof

Step Hyp Ref Expression
1 iunab ⊢ ∪ 𝑥 ∈ 𝐴 { 𝑦 ∣ ( 𝑦 ∈ 𝐵 ∧ 𝜑 ) } = { 𝑦 ∣ ∃ 𝑥 ∈ 𝐴 ( 𝑦 ∈ 𝐵 ∧ 𝜑 ) }
2 df-rab ⊢ { 𝑦 ∈ 𝐵 ∣ 𝜑 } = { 𝑦 ∣ ( 𝑦 ∈ 𝐵 ∧ 𝜑 ) }
3 2 a1i ⊢ ( 𝑥 ∈ 𝐴 → { 𝑦 ∈ 𝐵 ∣ 𝜑 } = { 𝑦 ∣ ( 𝑦 ∈ 𝐵 ∧ 𝜑 ) } )
4 3 iuneq2i ⊢ ∪ 𝑥 ∈ 𝐴 { 𝑦 ∈ 𝐵 ∣ 𝜑 } = ∪ 𝑥 ∈ 𝐴 { 𝑦 ∣ ( 𝑦 ∈ 𝐵 ∧ 𝜑 ) }
5 df-rab ⊢ { 𝑦 ∈ 𝐵 ∣ ∃ 𝑥 ∈ 𝐴 𝜑 } = { 𝑦 ∣ ( 𝑦 ∈ 𝐵 ∧ ∃ 𝑥 ∈ 𝐴 𝜑 ) }
6 r19.42v ⊢ ( ∃ 𝑥 ∈ 𝐴 ( 𝑦 ∈ 𝐵 ∧ 𝜑 ) ↔ ( 𝑦 ∈ 𝐵 ∧ ∃ 𝑥 ∈ 𝐴 𝜑 ) )
7 6 abbii ⊢ { 𝑦 ∣ ∃ 𝑥 ∈ 𝐴 ( 𝑦 ∈ 𝐵 ∧ 𝜑 ) } = { 𝑦 ∣ ( 𝑦 ∈ 𝐵 ∧ ∃ 𝑥 ∈ 𝐴 𝜑 ) }
8 5 7 eqtr4i ⊢ { 𝑦 ∈ 𝐵 ∣ ∃ 𝑥 ∈ 𝐴 𝜑 } = { 𝑦 ∣ ∃ 𝑥 ∈ 𝐴 ( 𝑦 ∈ 𝐵 ∧ 𝜑 ) }
9 1 4 8 3eqtr4i ⊢ ∪ 𝑥 ∈ 𝐴 { 𝑦 ∈ 𝐵 ∣ 𝜑 } = { 𝑦 ∈ 𝐵 ∣ ∃ 𝑥 ∈ 𝐴 𝜑 }