Metamath Proof Explorer


Theorem jca31

Description: Join three consequents. (Contributed by Jeff Hankins, 1-Aug-2009)

Ref Expression
Hypotheses jca31.1 ⊢ ( 𝜑 → 𝜓 )
jca31.2 ⊢ ( 𝜑 → 𝜒 )
jca31.3 ⊢ ( 𝜑 → 𝜃 )
Assertion jca31 ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) ∧ 𝜃 ) )

Proof

Step Hyp Ref Expression
1 jca31.1 ⊢ ( 𝜑 → 𝜓 )
2 jca31.2 ⊢ ( 𝜑 → 𝜒 )
3 jca31.3 ⊢ ( 𝜑 → 𝜃 )
4 1 2 jca ⊢ ( 𝜑 → ( 𝜓 ∧ 𝜒 ) )
5 4 3 jca ⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) ∧ 𝜃 ) )