Metamath Proof Explorer


Theorem l2p

Description: For any line in a planar incidence geometry, there exist two different points on the line. (Contributed by AV, 28-Nov-2021)

Ref Expression
Hypothesis l2p.1 ⊢ 𝑃 = ∪ 𝐺
Assertion l2p ( ( 𝐺 ∈ Plig ∧ 𝐿 ∈ 𝐺 ) → ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝐿 ∧ 𝑏 ∈ 𝐿 ) )

Proof

Step Hyp Ref Expression
1 l2p.1 ⊢ 𝑃 = ∪ 𝐺
2 1 isplig ⊢ ( 𝐺 ∈ Plig → ( 𝐺 ∈ Plig ↔ ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) ∧ ∀ 𝑙 ∈ 𝐺 ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ∧ ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ∃ 𝑐 ∈ 𝑃 ∀ 𝑙 ∈ 𝐺 ¬ ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ∧ 𝑐 ∈ 𝑙 ) ) ) )
3 eleq2 ⊢ ( 𝑙 = 𝐿 → ( 𝑎 ∈ 𝑙 ↔ 𝑎 ∈ 𝐿 ) )
4 eleq2 ⊢ ( 𝑙 = 𝐿 → ( 𝑏 ∈ 𝑙 ↔ 𝑏 ∈ 𝐿 ) )
5 3 4 3anbi23d ⊢ ( 𝑙 = 𝐿 → ( ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ↔ ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝐿 ∧ 𝑏 ∈ 𝐿 ) ) )
6 5 2rexbidv ⊢ ( 𝑙 = 𝐿 → ( ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ↔ ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝐿 ∧ 𝑏 ∈ 𝐿 ) ) )
7 6 rspccv ⊢ ( ∀ 𝑙 ∈ 𝐺 ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) → ( 𝐿 ∈ 𝐺 → ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝐿 ∧ 𝑏 ∈ 𝐿 ) ) )
8 7 3ad2ant2 ⊢ ( ( ∀ 𝑎 ∈ 𝑃 ∀ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 → ∃! 𝑙 ∈ 𝐺 ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ) ∧ ∀ 𝑙 ∈ 𝐺 ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ) ∧ ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ∃ 𝑐 ∈ 𝑃 ∀ 𝑙 ∈ 𝐺 ¬ ( 𝑎 ∈ 𝑙 ∧ 𝑏 ∈ 𝑙 ∧ 𝑐 ∈ 𝑙 ) ) → ( 𝐿 ∈ 𝐺 → ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝐿 ∧ 𝑏 ∈ 𝐿 ) ) )
9 2 8 biimtrdi ⊢ ( 𝐺 ∈ Plig → ( 𝐺 ∈ Plig → ( 𝐿 ∈ 𝐺 → ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝐿 ∧ 𝑏 ∈ 𝐿 ) ) ) )
10 9 pm2.43i ⊢ ( 𝐺 ∈ Plig → ( 𝐿 ∈ 𝐺 → ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝐿 ∧ 𝑏 ∈ 𝐿 ) ) )
11 10 imp ⊢ ( ( 𝐺 ∈ Plig ∧ 𝐿 ∈ 𝐺 ) → ∃ 𝑎 ∈ 𝑃 ∃ 𝑏 ∈ 𝑃 ( 𝑎 ≠ 𝑏 ∧ 𝑎 ∈ 𝐿 ∧ 𝑏 ∈ 𝐿 ) )